A natural number when divided by 3, 4, 5, 6 and 7 respectively, leaves corresponding reminders of 2, 3, 4, 5 and 6.What is the smallest of all such numbers fulfilling the above condition?
[1] 2519 [2] 419 [3] 209 [4] 839
Answer :-
[2] 419
Here
3 – 2 = 1, 4 –3 = 1, 5–4 =1, 6-5=1, 7-6= 1
∴ The required Number is = LCM of (3,4, 5, 6,7) – 1
= 420 – 1 = 419.
Hence option [2] is correct answer.
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