Every integer greater than1 is either a prime or a product of primes



We know that an integer n>1 is said to be a prime if it has no divisor other than ±1 and ±n itself.

That is if b|n and b>1, then b is =n ----------{ here b|n means b divides n.}

 

Example:-  2,3,5,7,11,,,,,,,,,,,,etc.

There is only one even prime number namely 2.

In other hand,

An integer n>1 is said to be composite if it is not a prime.

Note

 that 1 is neither a prime nor a composite; the natural numbers greater than 1 are divided into two groups, namely primes and composites.

Now, if n is composite or not prime, then n has a divisor greater than 1. If p is the least divisor of n and p>1, then p is necessarily a prime. It follows that every integer greater than 1 is either a prime or has a prime divisor.

If p is a prime dividing n.

That is;

If p|n, then n = px, where ……………….. 1 ≤ x ≤n.

Here if x = 1 then n is a prime, and if x>1 then we can write x as a product of prime p and x’ Like x = px’.

Thus, we see that every integer greater than 1 is either a prime or a product of primes.





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Mind blowing hard question

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