Popular methods of solving differential equation of first order and first degree.
1:- Variable separable method.
2:- Reducible to Variable separable method.
3:- Homogeneous differential equation .
4:- Reducible to Homogeneous differential equation .
5:- Linear differential equation.
6:- Reducible to Linear differential equation.
7:- Exact differential equation.
8:- Reducible to Exact differential equation.
1:- Variable separable method.
General Format;
f(x)dx + g(y)dy = 0
Solution is its integration,
ie, ∫f(x)dx + ∫g(y)dy = 0
Example,
(1+x²)dy = (1+y²)dx
=》∫dy/(1+y²)=∫dx/(1+x²)
=》tan‐¹y = tan‐¹x +c
Or
=》tan‐¹y = tan‐¹x +tan-¹c
=》tan‐¹y - tan‐¹x = tan-¹c
=》tan-¹[(y-x)/1+yx] = tan-¹c
=》[(y-x)/1+yx] = c
=》(y-x) = c(1+yx)
is the solution of this differential equation.
REDUCIBLE TO VARIABLE SEPARATION METHOD
When x and y can't be separated ,
Example:- (x+y)²dy/dx = a²
Then we let Linear form of ( ax+by+c) = v
Like ,
Let , x+y=v .................eq(1)
differenting with respect to x
=》 1 + dy/dx = dv/dx
=》 dy/dx = dv/dx - 1
by putting the value of dy/dx in question, so that,
=》(x+y)² (dv/dx - 1)= a²
Putting x+y as v , from eq(1)
=》(v)² (dv/dx - 1)= a²
=》dv/dx = a²/v² +1
=》dv/dx = (a²+v²)/v²
=》v²dv/ (a²+v²)= dx
Solution is,
=》∫v²dv/ (a²+v²)= ∫dx
=》∫{1-a²/(a²+v²)} dv= ∫dx
=》v - a²(1/a tan-¹x/a) = x + c
=》v - a.tan-¹(x/a) = x + c
replacing the value of v from eq(1) x+y=v
=》x+y - a.tan-¹(x/a) = x + c
=》y - a.tan-¹(x/a) = c
is the final answer. 🙌
Another example
Example number
2:- dy/dx =(3y+x+6)²
of Reducible to Variable separable method.
Solve,
Assuming the linear form 3y+x+6=v.............eq(1)
differenting with respect to x
=》3dy/dx +1 = dv/dx
=》dy/dx = (dv/dx -1)1/3
by putting the value of dy/dx in question, so that,
=》(dv/dx -1)1/3 =(3y+x+6)²
Putting (3y+x+6) as v , from eq(1)
=》(dv/dx -1)1/3 =(v)²
=》(dv/dx -1) =3(v)²
=》dv/dx = 3(v)²+1
=》dv / (3v)²+1) = dx
Solution is its integration,
=》∫dv / (3v)²+1) = ∫dx
After integration replace the value of v and get the real answer.
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